25=300-16t^2

Solution for 25=300-16t^2 equation:

25=300-16t^2

We move all terms to the left:

25-(300-16t^2)=0

We get rid of parentheses

16t^2-300+25=0

We add all the numbers together, and all the variables

16t^2-275=0

a = 16; b = 0; c = -275;
Δ = b2-4ac
Δ = 02-4·16·(-275)
Δ = 17600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17600}=\sqrt{1600*11}=\sqrt{1600}*\sqrt{11}=40\sqrt{11}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{11}}{2*16}=\frac{0-40\sqrt{11}}{32}
=-\frac{40\sqrt{11}}{32}
=-\frac{5\sqrt{11}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{11}}{2*16}=\frac{0+40\sqrt{11}}{32}
=\frac{40\sqrt{11}}{32}
=\frac{5\sqrt{11}}{4}
$